We have f(x) = 0;
Then x^2 - 1 - 2x - 2 = 0;
(x - 1)(x + 1) - 2(x + 1) = 0;
(x + 1)(x - 1 - 2) = 0;
(x + 1)(x - 3) = 0;
x + 1 = 0 or x - 3 = 0;
x = -1 or x = 3;
The zeroes of f are -1 and 3.
Answer:
2000000 bricks
Step-by-step explanation:
The computation of the number of bricks to be used is shown below:
The Volume of brick is
= (15 × 8 × 5)cm^3
= 600 cm^3
And, the Volume of wall is
= (1500 × 1000 × 800)cm^3
= 1200000000 cm^3
Now Bricks needed is
= 1200000000 cm^3 ÷ 600cm^3
= 2000000 bricks
Answer:
The simplest form is tan(4x)
Step-by-step explanation:
* Lets revise the identity of the compound angles
- 
- 
* Lets solve the problem
- Let 9x = 5x + 4x
∴ tan(9x) = tan(5x + 4x)
- Use the rule of the compound angle
∵ 
⇒ (1)
∵ 
⇒ (2)
∵ tan(9x) = equation (2)
- Substitute (2) in (1)
∴ 
- Multiply up and down by (1 - tan(5x)tan(4x))
∴ ![\frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%285x%29%2Btan%284x%29-tan%285x%29%5B1-tan%285x%29tan%284x%29%5D%7D%7B1-tan%285x%29tan%284x%29%2Btan%285x%29%5Btan%285x%29%2Btan%284x%29%5D%7D)
- Simplify up and down
∴ 
∴ ![\frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%284x%29%2Btan%5E%7B2%7D%285x%29tan%284x%29%7D%7B%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D)
- Take tan(4x) as a common factor up
∴ ![\frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}](https://tex.z-dn.net/?f=%5Cfrac%7Btan%284x%29%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D%7B%5B1%2Btan%5E%7B2%7D%285x%29%5D%7D)
- Cancel [1 + tan²(5x)] up and down
∴ The answer is tan(4x)
Answer: Hello Luv......
380 (There is no picture i'm sorry,)
Step-by-step explanation:
A = L + B = a2 + a√(a2 + 4h2))
Hope this helps. Mark me brainest please.
Anna ♥
