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ddd [48]
3 years ago
8

Please do part A and part B on number 9!

Mathematics
1 answer:
Mashcka [7]3 years ago
7 0

Answer:

A=5

B=4

Step-by-step explanatation

so the 3ft at the front and the 8ft at the back, you do 8-3 which is 5 which will be A and on the side, it is 8ft and since the corner angle is 4ft then B will be 8-4 which is 4

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find the slope of the line between each pair of points (5,11) (-3,-6) explain how you got the answer so I can see.
lorasvet [3.4K]
You can use slope formula to find slope of given points.
m = (y2-y1)/(x2-x1)
m = (-6-11)/(-3-5)
m = -17 / -8
Cancel out minus sign in both nominator and denominator. Thus,
m = 17/8
Hence, the slope is 17/8
4 0
3 years ago
What can you tell about the mean of each distribution
Llana [10]

Step-by-step explanation:

In the case of a discrete probability distribution of a random variable X, the mean is equal to the sum over every possible value weighted by the probability of that value; that is, it is computed by taking the product of each possible value x of X and its probability p(x), and then adding all these products together

5 0
3 years ago
Read 2 more answers
Which is closest to the circumference of the CD?
seropon [69]

Answer:

idk but heres an equation

Step-by-step explanation:

Since  

2

π

r

=

37.68

,

r

=

18.84

π

Area=  

π

⋅

(

18.84

)

2

π

2

=  

354.9456

3.14

= 113.04

5 0
3 years ago
Read 2 more answers
The mean of Alice's last 5 math test scores is 88. The first 4 of these 5 math test scores were 87, 75, 93, and 85. What score d
stiks02 [169]

Answer:

Step-by-step explanation:

x is the score she got on the fifth test.

Since her average score is 88, the sum of all five tests is 5×88.

x + 87 + 75 + 93 + 85 = 5×88 = 440

x = 440 -  87 - 75 - 93 - 85

x = 100

She got a 100 on her fifth test.

6 0
3 years ago
WILL MARK BRAINLIEST
dsp73
<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
  5. Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0
3 years ago
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