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2 years ago

Which equation represents the horizontal line passing through (5, 3)?

Mathematics

1 answer:

Viktor [21]2 years ago

7 0

Step-by-step explanation:

General equation for horizontal line: y = a

Since the point (5, 3) has y-value 3,

the equation of the horizontal line is y = 3.

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Sanjay read 56 pages of his book this weekend.This is 35% of the pages in the book.How many pages are in Sanjays book?

Maurinko [17]

1. 56 : 35 = 1.6
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3 years ago

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tester [92]

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3 years ago

(NEED EVIDENCE, NOT ONLY ANSWER)

bearhunter [10]

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2 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago

Plz help.. plzz if you can

Mazyrski [523]

Answer:

C is a function

Step-by-step explanation:

We can use the vertical line test. If a vertical straight lines passes through the graph more than one, it is not a function

A and B are not functions

C is a function

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2 years ago