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matrenka [14]
2 years ago
14

A small airplane can carry less

Mathematics
1 answer:
enyata [817]2 years ago
4 0
840 = 480 + 60x

answer is x = 6
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WILL GIVE BRAINLIEST Pump it Up gym's daily revenue each can be modeled by R(x) = 5x where x represents the number of customers
Alexxx [7]

Answer:

P(x) = 3x - 150

Step-by-step explanation:

Step-by-step explanation:

P(x) = R(x) - C(x)

Given:

R(x) = 5x

C(x) = 2x + 150

P(x) = 5x -(2x+150)

P(x) = 5x - 2x -150

P(x) = 3x - 150 <- Answer

6 0
3 years ago
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Shakira went bowling with her friends. She paid $3 to rent shoes and then $4.75 for each game of bowling. If she spent a total o
Marina CMI [18]

x = # of games playing.

4.75x + 3 = 42

4.75x = 39

      x = 39 /4.75

      x = 8.21

Answer:

Shakira played about 8 games

4 0
2 years ago
If u guess a number 1-50 and get it right I will give u branliest
gulaghasi [49]

My guess is 50 Or 30

5 0
3 years ago
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The circumstance of a circle is 36pi inches what is the radius for this circle
frez [133]

Circumference = 2pi*r

r = radius

In our problem,

circumference = 36pi

r = ?

Let's plug our values into the formula above.

36pi = 2pi * r

Divide both sides by 2pi

18 = r

4 0
2 years ago
Given the following trigonometric ratio, enumerate the meaning ratio ​
Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

\sin \theta = \frac{y}{h} (1)

Cosine

\cos \theta = \frac{x}{h} (2)

Tangent

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x} (3)

Cotangent

\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y} (4)

Secant

\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x} (5)

Cosecant

\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y} (6)

Where:

x - Adjacent leg.

y - Opposite leg.

h - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

h = \sqrt{x^{2}+y^{2}}

If y = AC and x = BC, then the trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

6 0
3 years ago
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