-5y+8=-3y+10
-5y+3y=10-8
-2y=2
-2y/-2=2/-2
y=-1
I grouped the alike variable to one side, and the number to the other side, added and subtracted it, divided both sides by -2, and got -1
Answer:
Aight bet, so it's 74 degrees Fahrenheit at the moment, and it takes one hour for it to increase by 2 degrees, so what I would do, is 87 minus 74, which equals to 13, 13 is an odd number of course, but, let's put it at 12 first and do the remaining 1 later, so it's 12, so divide 12 by 2, equals to 6, so for now, 6 hours, then, the remaining 1 degree, as it takes two degrees PER hour, and 1 is half of 2, 1 degree will take 30 mins, so 6 hours and 30 mins.
It will take 6 hours and 30 minutes for the temperature from 74 degrees to increase to 87 degrees.
Step-by-step explanation:
Believe it or not, :), the width of the ribbon needs to be known to get the right answer. If the ribbon had an infinitely small width the ribbon needed would just be the perimeter.
P=2(L+W)
P=2(12+15)
P=54 in
However an infinitely small width is not something that has any practical application. For example, if the width of the ribbon were 1/2 in.
P=2((L+1)+W)
P=2(16+12)
P=56 in So the perimeter increased by 2 in when the ribbon was only 1/2 in wide.
The "infinitely small" width and the perimeter of 54 in is only a decent approximation if the ribbon were a very thin string.
In an algebra problem, you don't set the answer-goal and say "Go for it!"
There is only one correct answer, so the only appropriate way to go about it is to say "Here is the equation. Find the solution.?"
Maybe 27 is the solution, and maybe it's not.
We're about to find out.
You said 2/3 x - 7 = 11
Add 7 to each side: 2/3 x = 18
Divide each side by 2 : 1/3 x = 9
Multiply each side by 3 : x = 27 .
So yes, the correct solution is 27. And that's how to find it.
Y-5=3(x+1)
y-5=3x+3
add 5 to both sides
the answer would be y=3x+8