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Contact [7]
3 years ago
5

Greg buys apples, bananas, and kiwis from a fruit stand each week. The first week he pays $3.19 for 2 apples, 3 bananas, and 2 k

iwis. The second week he pays $4.12 for 3 apples, 4 bananas, and 2 kiwis. The third week he pays $3.01 for 1 apple, 1 banana, and 4 kiwis. Choose the system of equations that can be used to solve for the number of apples,a, the number of bananas,b, and the number of kiwis,k.
Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Answer:

Step-by-step explanation:

2a+3b+2k= $3.19

3a+4b+2k=$4.12

1a+1b+4k=$3.01

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4 years ago
This season, Lisa's lacrosse team has won $\frac 23 of their home games (games played at Lisa's school), but just $\frac 25 of t
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Answer:

Lisa's team have played 24 home games and 25 away games.

Step-by-step explanation:

Given:

Let x represents games played at home.

also y represent games played away.

Total number of games played = 49

∴ x+y=49 \ \ \ \  equation \ 1

Now according to given data:

Number of home games won = \frac{2}{3}

Number of away game won = \frac{2}{5}

Total games won =26

Hence

\frac{2}{3}x+\frac{2}{5}y=26\\\\\frac{2\times 5}{3\times 5}x+\frac{2\times 3}{5\times 5}y=26\\\\\frac{10}{15}x+\frac{6}{15}y=26\\\\\frac{10x+6y}{15}=26\\\\10x+6y= 26\times 15\\10x+6y = 390\\2(5x+3y)=390\\5x+3y=\frac{390}{5}\\\\5x+3y=195 \ \ \ \ equation \ 2\\

Now multiplying equation 1 by 3 we get,

3(x+y)=3\times49\\3x+3y=147 \ \ \ \ \ equation \ 3\\

Now Subtracting equation 2 by equation 3 we get,

(5x+3y=195)-(3x+3y=147)\\2x=48\\x= \frac{48}{2}=24

Substituting value of x in equation 1 we get.

x+y=49\\24+y=49\\y=49-24=25

Hence Lisa's team have played 24 home games and 25 away games.

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