Answer:
2
Step-by-step explanation:
Answer:
lyrics d - 1.782
Step-by-step explanation:
Assume Normal Distribution
we have μ₀ = 40 (from Dullco claims)
And from sample μ = 37.8 and standard deviation of 5.4
random sample n = 18
We have to use t-student for testing the hypothesis
and we have a one tail test (left) since Dullco claims : " at least" meaning (always bigger or at least ) not different.
Then
t (s) =( μ - μ₀) / (σ/√n) ⇒ t (s) = [(37.8 - 40 )* √18 ]/5.4
t (s) = - 1.7284
The required probability is
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that,
Probability for first draw to be non-defective
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective
(printers after first slot = 10; total defective printers = 2)
Then, total probability
Answer:
i believe luis... sorry if i'm wrong!!
Step-by-step explanation:
luis has the most and there isnt 11 in 10, so i'm guessing it would be 6/7..luis
Answer:
360°
Step-by-step explanation:
degrees are needed