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aivan3 [116]
3 years ago
10

Need help plz it’s only one question!!!

Mathematics
2 answers:
kipiarov [429]3 years ago
5 0
Owns $12 and 50 cents
Semenov [28]3 years ago
3 0
2.50 (5) = 12.5

she owes 12 dollars and 50 cents
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X^2+6x=68 I think but I’m not sure
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The ratio of clown fish to angel fish in a pet store is 5:4. The ratio of angel fish to gold fish is 4:3. There are 60 Clown fis
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4 years ago
For what non-zero value of x,
prisoha [69]

Answer:

  • d) 1/(4p²)

Step-by-step explanation:

<u>Let's complete the square first:</u>

  • p⁴ - 2p²x² + x⁴ + x =
  • p⁴ + 2p²x² + x⁴ - 4p²x² + x =
  • (p² + x²)² - (4p²x² - x)

<u>In order the expression above to be a perfect square, we need:</u>

  • 4p²x² - x = 0

<u>Solve it for x:</u>

  • 4p²x² = x
  • 4p²x = 1
  • x = 1/(4p²)

Correct choice is d

4 0
2 years ago
What kind of conditions did olaudah equiano experience aboard the ship? Use evidence from the excerpt above to support your answ
zmey [24]

Answer:

Equiano responds with shock and horror to the conditions he describes aboard the slave ship on the Middle Passage. Equiano is struck by the claustrophobic conditions below decks, and describes in lurid detail the smells of sweat and human waste as well as the screams and moans of slaves confined in these awful conditions

Step-by-step explanation:

8 0
3 years ago
Consider the following initial-value problem. Y'' − 5y' = 8e4t − 4e−t, y(0) = 1, y'(0) = −1 find ℒ{f(t)}, for f(t) = 8e4t − 4e−t
Nataliya [291]

The <em>Laplace</em> transform of the <em>non-homogeneous second order differential</em> equation is \mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}.

<h3>How to determine the Laplace transform of a non-homogeneous second order differential equation </h3>

A <em>Laplace</em> transform is a <em>frequency-based algebraic</em> substitution method used to determine the solutions of <em>differential</em> equations in a quick and efficient manner.

In this question we shall use the following <em>Laplace</em> transforms:

\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}   (1)

\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}   (2)

\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)   (3)

\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}   (4)

Now we proceed to derive an expression fo the <em>Laplace</em> transform of the solution of the <em>differential</em> equation:

y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}

s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}

\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}

The <em>Laplace</em> transform of the <em>non-homogeneous second order differential</em> equation is \mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}. \blacksquare

To learn more on Laplace transforms, we kindl invite to check this verified question: brainly.com/question/2272409

5 0
2 years ago
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