Need help plz it’s only one question!!!

What number needs to be added to both sides of the equation in order to

postnew [5]

X^2+6x=68 I think but I’m not sure

3 0

3 years ago

The ratio of clown fish to angel fish in a pet store is 5:4. The ratio of angel fish to gold fish is 4:3. There are 60 Clown fis

scoundrel [369]

There are 48 angelfish and 36 goldfish

6 0

4 years ago

For what non-zero value of x,

prisoha [69]

Answer:

d) 1/(4p²)

Step-by-step explanation:

Let's complete the square first:

p⁴ - 2p²x² + x⁴ + x =
p⁴ + 2p²x² + x⁴ - 4p²x² + x =
(p² + x²)² - (4p²x² - x)

In order the expression above to be a perfect square, we need:

4p²x² - x = 0

Solve it for x:

4p²x² = x
4p²x = 1
x = 1/(4p²)

Correct choice is d

4 0

2 years ago

What kind of conditions did olaudah equiano experience aboard the ship? Use evidence from the excerpt above to support your answ

zmey [24]

Answer:

Equiano responds with shock and horror to the conditions he describes aboard the slave ship on the Middle Passage. Equiano is struck by the claustrophobic conditions below decks, and describes in lurid detail the smells of sweat and human waste as well as the screams and moans of slaves confined in these awful conditions

Step-by-step explanation:

8 0

3 years ago

Consider the following initial-value problem. Y'' − 5y' = 8e4t − 4e−t, y(0) = 1, y'(0) = −1 find ℒ{f(t)}, for f(t) = 8e4t − 4e−t

Nataliya [291]

The Laplace transform of the non-homogeneous second order differential equation is $\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}$ .

<h3>How to determine the Laplace transform of a non-homogeneous second order differential equation </h3>

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations in a quick and efficient manner.

In this question we shall use the following Laplace transforms:

$\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}$ (1)

$\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}$ (2)

$\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)$ (3)

$\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}$ (4)

Now we proceed to derive an expression fo the Laplace transform of the solution of the differential equation:

$y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}$

$s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}$

$\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}$

The Laplace transform of the non-homogeneous second order differential equation is $\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}$ . $\blacksquare$

To learn more on Laplace transforms, we kindl invite to check this verified question: brainly.com/question/2272409

5 0

2 years ago