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sdas [7]
3 years ago
14

Need help with box and whiskers plot pls ill give brainliest (answer all 4 questions if can)

Mathematics
1 answer:
mina [271]3 years ago
8 0
1. 10
2. 25
3. 40
4. 30
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What are the steps to solving this limit?
patriot [66]

Answer:

lim(x---->0) = -5

Step-by-step explanation:

first: sin(x-π/2)= -cosx

so the equation will be :

lim(x---->0) = [-6cos(ax)-1}/cosx

solve :

lim(x---->0) =  [-(6cos(a(0))-1}/cos(0)

cos0=1

lim(x---->0)=(-(6(1)-1)/1

lim(x---->0)=-6+1/1

lim(x---->0)=-5

6 0
3 years ago
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Y = 5x + 1<br> 4x + y = 10<br> System of equations
HACTEHA [7]
Substitution or elimination
3 0
3 years ago
I need to find the slope
dangina [55]

Answer:

1/-4

Step-by-step explanation:

(2,-3),(-2,-2)

-2 + 3/ -2 - 2

1/-4

6 0
4 years ago
Please help i am stuck on this for more than a day
Mila [183]
252 seeds

Since there is 42 seeds in each of the 12 bags you need to multiply 42 and 12

42 × 12 = 504

So in total she has 504 seeds, now you need to split that in half by dividing 504 and 2

504 ÷ 2 = 252

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Hope this helps! :)
6 0
3 years ago
Two circles, one of radius 5 inches, the other of radius 2 inches, are tangent at point P. Two bugs start crawling at the same t
lawyer [7]

Answer:

  40 minutes

Step-by-step explanation:

The circumference of the larger circle is ...

  C = 2πr = 2π(5 in) = 10π in

The bug navigates the circumference at 3π in/min, so will take

  time = distance/speed = (10π in)/(3π in/min) = 10/3 min

to travel once around.

__

The circumference of the smaller circle is ...

  C = 2πr = 2π(2 in) = 4π in

The bug navigates this circumference at 2.5π in/min, so will take

  (4π in)/(2.5π in/min) = 8/5 min

to travel once around.

__

The bugs will meet at a time that is the least common multiple of these times. Both can be expressed in 15ths of a minute as ...

  {50/15, 24/15}

Then the LCM of these will be ...

  (1/15)LCM(50, 24) = (1/15)(50×24)/GCD(50, 24) = 1200/30 = 40

It will be 40 minutes before the bugs next meet at point P.

___

A graphing calculator can make use of the mod function to show when the bugs meet at point P (total is displacement of the two bugs from P is zero). It shows the meeting occurs after 40 minutes.

5 0
4 years ago
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