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3 years ago

0.25×m = 3.6 m=_____.

Mathematics

1 answer:

Vlada [557]3 years ago

8 0

0.25xm = 3.6m = m=0
Hope this answer helps

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Write the equation of a line parallel to the line y = 2x that passes through -2,-1

maksim [4K]

Answer:

y = 2x + 3

Step-by-step explanation:

A line parallel to y = 2x has exactly the same slope but a different y-intercept, b.

Start with y = mx + b, and replace m with 2, y with -1 and x with -2:

-1 = 2(-2) + b, or

-1 = -4 + b.

Then b = 3, and the desired equation is y = 2x + 3

7 0

3 years ago

Read 2 more answers

I need help fast thx

andre [41]

T will travel 81 m/s because addin six to 21 gives you 27 so take that times three and you get 81 m/s hope this helps

7 0

4 years ago

Y= x - 4<br> 5x+y=-34<br> How would I do this in steps ?

Lostsunrise [7]

Answer:

x = -5 y = -9

Step-by-step explanation:

y = x -4

5x + y = - 34

substitute x-4 in for y to solve for x

5x + x - 4 = 34

solve for x . . . add 5x + x = 6x

so you now have 6x-4 = -34

add 4 to both sides of the equation

6x-4 + 4 = -34+ 4

6x = -30

divide both sides by 6

6x/6 = -30/6

x= -5

then you plug -5 for x in the first equation

y = x - 4

y= -5 -4

y =-9

x= -5 y= -9

8 0

3 years ago

A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his s

Hunter-Best [27]

Answer:

d) The difference exists due to chance since the test statistic is small

Step-by-step explanation:

From the given information:

Population mean = 178 cm

the sample mean = 177.5 cm

the standard deviation = 2

the sample size = 25

The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

$H_o: \mu = 178$

Alternative hypothesis:

$H_1: \mu \neq 178$

The t-test statistics is determined by using the formula:

$t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

$t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}$

$t = \dfrac{-0.5}{\dfrac{2}{5}}}$

$\mathbf{t= -1.25}$

Degree of freedom df = n- 1

Degree of freedom df = 25 - 1

Degree of freedom df = 24

At the level of significance ∝ = 0.05, the critical value = 2.064

Decision rule: To reject the null hypothesis if the test statistics is greater than the critical value at 0.05 level of significance

Conclusion: We fail to reject the null hypothesis since the test statistics is lesser than the critical value and we conclude that the difference exists due to chance since the test statistic is small

5 0

3 years ago

Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!

kvasek [131]

Hello,

Answer D

x²/25+y²/16=1

5 0

4 years ago