If you are proving a congruence of triangles then you need to match the corresponding parts to the triangle you are proving congruent.
BAC would then be congruent to MJR because of the corresponding angles
B is the same angle as M
A is the same angle as J
C is the same angle as R
These seem tough, but they are not that bad.
(f o g)(x)
That means to take function g when x = x (It just means that you don't need to do anything with the function) and substitute it into function f wherever there is a x value. (So basically g becomes what x equals)
Here is a visual representation of it.
(f o g)(x) = 2(9x + (3/2)) - (3/9)
We need to distribute the 2 to everything inside the parenthesis.
(f o g)(x) = 18x + (6/2) - (3/9)
Let's simplify the fraction on the right and left, then find a common denominator so we can add / subtract the two fractions.
(f o g)(x) = 18x + (3) - (1/3)
(f o g)(x) = 18x + (9/3) - (1/3)
Combine like terms.
(f o g)(x) = 18x + (8/3)
Our final answer is:
(f o g)(x) = 18x + 8/3
Answer:
54 is the area
Step-by-step explanation:
you do 6 x 9=54
3 x 15 = 45
3 x 14 = 42
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There are 14 packages.
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x = 42/3
-----> 3x=42
