Simply find the difference between the intercept and axis of symmetry then apply it to the other side
-1 › 3 = 4
so
3 + 4 = 7
The optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
<h3><u>
Solution:</u></h3>
Given that,
<h3><u>The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by:</u></h3>
![d = 1.9[(5.5 \times 10^{-4})l]^{\frac{1}{2}}](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29l%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
where l is the length (in millimeters) of the camera box
<h3><u>Find the optimum pinhole diameter for a camera box with a length of 10 centimeters</u></h3>
l = 10 cm
We know that,
10 cm = 100 mm
<em><u>Therefore, plug in l = 100 in given formula</u></em>
![d = 1.9[(5.5 \times 10^{-4}) \times 100]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-4} \times 10^2]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-2}]^{\frac{1}{2}}\\\\d = 1.9 \times 5.5^{\frac{1}{2} \times 10^{-1}}\\\\d = 0.19 \times 2.345207\\\\d = 0.4455 \approx 0.446](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29%20%5Ctimes%20100%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctimes%2010%5E2%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-2%7D%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%20%5Ctimes%205.5%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2010%5E%7B-1%7D%7D%5C%5C%5C%5Cd%20%3D%200.19%20%5Ctimes%202.345207%5C%5C%5C%5Cd%20%3D%200.4455%20%5Capprox%200.446)
Thus the optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
Answer:
I thank it is 1753.4
Step-by-step explanation:
i hope its right
It would be 25.6 with a dash on top of the number 6
Answer:
The amount of change in the balance of the account is an increase of $3160.57.
Step-by-step explanation:
i) first deposit is given as $1250
ii) second deposit is given as $3040.57
iii) first withdrawal is given as $400
iv) second withdrawal is given as $400
v) third withdrawal is given as $400
vi) first penalty removed is $35
vii) second penalty removed is $35
viii) therefore the change to the balance is given by
$1250 + $3040.57 - $400 - $400 - $400 + $35 + $35 = $3160.57
viii) Therefore the amount of change in the balance of the account is an increase of $3160.57.