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3 years ago

Help needed, much appreciated

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

3 0

Answer:

1/6

Explain:

The reciprocal of the slope is its perpendicular.

6/1 --> 1/6

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In ΔTUV, the measure of ∠V=90°, the measure of ∠T=16°, and VT = 4.9 feet. Find the length of TU to the nearest tenth of a foot.

RSB [31]

<u>Given</u>:

Given that TUV is a right triangle.

The measure of ∠T is 16°

The length of VT is 4.9 feet.

We need to determine the length of TU.

<u>Length of TU:</u>

The length of TU can be determined using the trigonometric ratio.

Thus, we have;

$cos \ \theta=\frac{adj}{hyp}$

where $\theta=16^{\circ}$ , adj = TV and hyp = TU

Thus, we get;

$cos \ 16^{\circ}=\frac{4.9}{TU}$

Simplifying, we get;

$TU=\frac{4.9}{cos \ 16^{\circ}}$

$TU=\frac{4.9}{0.9613}$

$TU=5.097$

Rounding off to the nearest tenth, we get;

$TU=5.1$

Thus, the length of TU is 5.1 feet.

6 0

3 years ago

The value of y varies directly with x. When x = 5, y = 7.5. What is the value of y when x = 15?

aliina [53]

Answer:

22.5

Step-by-step explanation:

SINCE Y VARIES DIRECTLY WITH X, WE USE THE FORMULA

y=kx; k representing the variable change, y= 7.5, x=5

> y=kx

>7.5= k(5) > 7.5= 5k

>k= 7.5/5 (divide to get the k)

k= 1.5

NOW REPLACE THE NEW VALUES OF X AND K AS THE VARIABLE CHANGE, TO FIND THE VALUE OF Y

>y=kx ; k=1.5 and x=15 y=?

>y= (1.5)(15)

>y=22.5

the value of y is 22.5 when x is 15

5 0

3 years ago

Write an equation that represents the line passing through the point -3, -1 with a slope of 4

Alex17521 [72]

Answer:

Equation that represents the line passing through the point -3, -1 with a slope of 4 is

$y= 4x+11$

Step-by-step explanation:

Equation of line in point slope form is

$y-y_1=m(x-x_1)$ -------(1)

Here

$m=4 \ \ \ and \ \ \ (x_1, y_1) = (-3, -1)$

Substituting values in equation (1)

$y+1=4(x+3)\\ y= 4x+11$

4 0

3 years ago

How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2. X 2 6x – 4y = –10 one

nordsb [41]

The system of equations provides a unique solution(one solution) at (-0.6, 1.6).

<h2>Given to us,</h2>

$y=\dfrac{2}{3}x+2$
$6x-4y=-10$

<h3>Equation 2</h3>

As we already have the value of y from equation 1, substitute its value in equation 2,

$6x-4y=-10$

$6x-4(\dfrac{2}{3}x+2)=-10$

$6x-\dfrac{8}{3}x-8=-10$

$\dfrac{6x}{1}-\dfrac{8}{3}x=-10+8$

$\dfrac{6x\times 3}{1\times 3}-\dfrac{8}{3}x=-2$

$\dfrac{18x-8x}{3}=-2$

$10x=-6\\$

$x=\dfrac{-6}{10} \\\\x=-0.6$

<h3>Equation 1,</h3>

$y=\dfrac{2}{3}x+2$

substitute the value of x in equation 1,

$y=\dfrac{2}{3}(\dfrac{-6}{10})+2\\\\y = \dfrac{-2}{5}+2\\\\y= \dfrac{-2+10}{5}\\\\y = \dfrac{8}{5}\\\\y=1.6$

As we can see the system of equations provides a unique solution(one solution) at (-0.6, 1.6).

Learn more about the system of equations:

brainly.com/question/12895249

3 0

3 years ago

When ∆RST is translated 4 units down, what are the apparent coordinates of T’?

Klio2033 [76]

Answer:

T' is at (-1,-8)

Step-by-step explanation:

When we translate down 4 units, we will subtract 4 from the y coordinate

T is at (-1,-4)

We need to subtract 4 from the y coordinate

T' is at (-1,-4-4)

T' is at (-1,-8)

4 0

3 years ago