3 years ago

A school surveyed its

Mathematics

1 answer:

Alinara [238K]3 years ago

6 0

Answer:

12.5%

Step-by-step explanation:

You might be interested in

How to put 3 and 5 hundredths in standard form

astraxan [27]

In standard for its either 3 5/100 or 3.05

3 0

3 years ago

A class sold tickets to their school play. Each of the 23 students in the class sold 4 tickets. The cost of each ticket was $7.H

Gnoma [55]

$7•4 tickets=$28every student
$28•23=$644
$644 the amount of money the class earned

6 0

3 years ago

Sara must plant 340 trees. In the past 6 days Sara planted 204 trees. If she continues at this rate, how many more days will it

ikadub [295]

204/6 = 34 trees a day. 340-204 =136 trees left to plant. 136/34 = 4 4 days

4 0

4 years ago

Triangle TAB has a perimeter of 40 cm. Could the measures of the sides, as shown, actually represent the measures of the sides o

zzz [600]

Answer:

yes

Step-by-step explanation:

3 0

3 years ago

In a large lecture course, the scores on the final examination followed the normal curve closely. The average score was 60 point

Anna35 [415]

Answer:

The value is $\sigma = 31.35$

Step-by-step explanation:

From the question we are told that

The average score is $\mu = 60$

Generally the probability that $\frac{1}{4} = 0.25$ of the class score is between 50 and 70 points is mathematically represented as

$P(50 < X < 70)= P(\frac{50 - 60 }{\sigma } < \frac{X - \mu }{\sigma} < \frac{70 - 60}{\sigma } ) = 0.25$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P(50 < X < 70)= P(\frac{-10 }{\sigma } < Z < \frac{10}{\sigma } ) = 0.25$

=> $P(50 < X < 70)= P(Z < \frac{10 }{\sigma }) -(Z < \frac{-10}{\sigma } )= 0.25$

=> $P(50 < X < 70)= 2P(Z < \frac{10 }{\sigma }) = 0.25$

From the normal distribution table the critical value of 0.25 for a two tailed test is z= 0.318

$\frac{10}{\sigma } = 0.319$

=> $\sigma = 31.35$

8 0

3 years ago