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Vladimir79 [104]
3 years ago
8

How do you find a slope in a line

Mathematics
2 answers:
givi [52]3 years ago
8 0
The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .
mixer [17]3 years ago
4 0

Answer:

Figure out the rise and the run.

Step-by-step explanation:

This picture might be more simple for understanding how.

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Tammy is selling tickets for the school jazz band concert. Adult tickets cost $5, and student tickets cost $3. If Tammy sells a
N76 [4]
Adult+student=170 ----(1)
5adult+3student=650 ----(2)

(1)*3; 3adult+3student=510 ----(3)
(2)-(3); 2adult = 140
so adult = 70
then student = 170-70 = 100

answer: Tammy sold 70 adult tickets and 100 student tickets
4 0
3 years ago
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Janes salary is increased by 4% to $15600. How much was her salary before the rise?
katovenus [111]
You have to make 4% into a decimal which is.04 then multiply 15600 x .04 which equals 624
4 0
4 years ago
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Felicia’s mother is four times as old as Felicia. In 16 years, her mother will be twice her age. How old is Felicia now?
dexar [7]

Answer:

16

Step-by-step explanation:

Now:16 x 2 = 32

16 years:32 x 2 =64

64 / 2 = 32

6 0
3 years ago
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Find the population density of each state. round to the nearest 10th.
matrenka [14]
Population density = population/area

Califonia = 36,500,000 / 163,707 = 223.0 persons per square mile
Florida = 18,300,000 / 65,758 = 278.3 persons per square mile
Iowa = 2,990,000 / 56,276 = 53.1 persons per square mile
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3 0
3 years ago
5.–/1 points SCalcET8 3.8.011. Ask Your Teacher My Notes Question Part Points Submissions Used Scientist can determine the age o
Vilka [71]

Answer:

  • 13,200 years

Explanation:

These steps explain how you estimate the age of the parchment:

1) Carbon - 14 half-life: τ = 5730 years

2) Number of half-lives elapsed: n

3) Age of the parchment = τ×n = 5730×n years = 5730n

4) Exponential decay:

The ratio of the final amount of the radioactive isotope C-14 to the initial amount of the same is one half (1/2) raised to the number of half-lives elapsed (n):

  • A / Ao = (1/2)ⁿ

5) The parchment fragment  had about 74% as much C-14 radioactivity as does plant material on Earth today:

  • ⇒ A / Ao = 74% = 0.74

  • ⇒ A / Ao =  0.74 = (1/2)ⁿ

  • ⇒ ln (0.74) = n ln (1/2)        [apply natural logarithm to both sides]

  • ⇒ n = ln (1/2) / ln (0.74)

  • ⇒ n ≈ - 0.693 / ( - 0.301) = 2.30

Hence, 2.30 half-lives have elapsed and the age of the parchment is:

  • τ×n = 5730n = 5730 (2.30) = 13,179 years

  • Round to the nearest hundred years: 13,200 years
7 0
3 years ago
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