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3 years ago

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Got 5 Questions I need help on!

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photoshop1234 [79]3 years ago

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Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

Select the correct answer. Segment KL is a diameter of circle Q. Circle Q is represented by the equation (x − 11)2 + (y + 15)2 =

m_a_m_a [10]

Answer:

2√7

Step-by-step explanation:

Mathematically, the equation of a circle can be represented by;

(x-h)^2 + (y-k)^2 = r^2

where (h,k) = center and r = radius

Applying this to the question, we can see that the length of the radius of the circle is √7

The diameter is always twice the radius

Thus, the diameter KL = 2 * √7 = 2√7

7 0

2 years ago

Express 12,312,087 in words

Sav [38]

Twelve million, three hundred twelve thousand, eighty-seven

4 0

2 years ago

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I need help with math please!!!!!!

nevsk [136]

24 is the answer i really dont know ok just try your best

3 0

2 years ago

ANswer pls correctly Ill mark as brainleist im always online as soon as i get answer ill give brainliest

schepotkina [342]

if we subtract from 65° the subangle of 37°, what we're left with is an angle off 65° - 37°, Check the picture below.

4 0

2 years ago

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