Answer:
C
Step-by-step explanation:
-2x + 7= 3x -8
+8
-2x + 15=3x
+2x
15=5x
divide
x=3
put 3 in one of the equations
y= 3(3) - 8
y=9-8 = y=1
answer is c
:))))
Answer:
(x - 6)(x + 5)
Step-by-step explanation:
You know that in order to get x^2 there has to be two x's so you get:
(x ...)(x...)
Then you also know that two numbers have to multiply together and equal 30 but also have a sume of -1. So you get:
(x - 6)(x + 5)
Answer:
y = 3x
Step-by-step explanation:
Given
9x - y = - 6x + 4y ( subtract 4y from both sides )
9x - 5y = - 6x ( subtract 9x from both sides )
- 5y = - 15x ( divide both sides by - 5 )
y = 3x
1 can of wet food
_
3 cans of wet food
Or
1:3
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
