Answer:
Step-by-step explanation:
The explicit formula for an arithmetic sequence is
where n is the position of the number in the sequence, a1 is the first number in the sequence, and d is the common difference between the numbers.
If we are looking for the 91st term, our n = 91;
our a1 is 28, and
the common difference is -20. Putting all that together gives us the explicit formula for this sequence:
and
and
so
C.) 0.0001 is a power of ten
Answer: Choice E
multiply to give a*c and add to get b
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This is known as the AC factoring method based on how you multiply the first and last coefficients (a and c) and use that product to figure out which factors add to the middle coefficient.
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An example:
6x^2 + 35x + 50
We have a = 6, b = 35, c = 50
Multiply a and c and we get: a*c = 6*50 = 300
We need to find factors of 300 that pair up and add to 35
Through trial and error you should find,
15 * 20 = 300
15 + 20 = 35
The two numbers are therefore 15 and 20.
So we break 35x into 15x+20x and use the factor by grouping method
6x^2 + 35x + 50
6x^2 + 15x + 20x + 50
(6x^2 + 15x) + (20x + 50)
3x(2x + 5) + 10(2x + 5)
(3x + 10)(2x + 5)
We see that 6x^2 + 35x + 50 factors to (3x + 10)(2x + 5)
Use the FOIL method or the box method or distribution to help see that (3x + 10)(2x + 5) expands back to 6x^2 + 35x + 50.
Answer:
A's received by Dina is 35.
Step-by-step explanation:
Given
number of A’s received by Pete, Chris, and Dina on their report cards were in a ratio of 4:2:5.
Let the
A's received by Pete = 4x
A's received by Chris = 2x
A's received by Dina = 5x
This, is done so that ratio of 4:2:5 remains intact.
Now, given Pete got 14 more A’s than Chris got
Thus, writing it mathematically
A's got by Pete = A's got be Chris + 14
we will be using A's got Pete and Chris in term of x as defined above
4x = 2x+ 14
=> 4x - 2x = 14
=> 2x = 14
=> x = 14/2 = 7
A's received by Dina = 5x = 5*7 = 35( Answer).
Answer:
<h2>60 ft long bc that would leave 10ft on each side of the banner...</h2>
Step-by-step explanation:
<h2>Hopes this helps. Mark as brainlest plz!</h2>
