Ask question

Ask question

All categories

Veseljchak [2.6K]

3 years ago

11

0.11764705882 as a fraction

2 answers:

iris [78.8K]3 years ago

6 0

Round it off as .11 your fraction will be
11/100

klemol [59]3 years ago

3 0

Answer:

5882352941 / 50000000000

You might be interested in

I dont know how to do this pls help

Alecsey [184]

Answer:

1) 225

2) 2304

Step-by-step explanation:

1)

Use geometric mean of legs

$x = \sqrt{(16+9)^2 * 9^2} = \sqrt{25^2 * 9^2} = 25 * 9 = 225$

2)

Use geometric mean of altitude

$x = \sqrt{(100-36)^2 * 36^2} = \sqrt{64^2 * 36^2} = 64 * 36 = 2304$

5 0

3 years ago

I have four factors 3 of my factors are 1,2,and 6 what is my fourth factor

Naddik [55]

12
2 multiplied by 6 is 12 and so 1 multiplied by something is 12
Hope this helps.

7 0

3 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth of a unit. Both 9 and 10 please.

Anestetic [448]

Problem 9
By definition,
$tan 22^{o} = \frac{203}{x} \\ 0.404 = \frac{203}{x} \\ x = \frac{203}{0.404}= 502.44$

Answer: 502.4 m

Problem 10
From geometry, the angle opposite x is 27°.
By definition,
$sin 27^{o} = \frac{x}{580} \\ 0.454 = \frac{x}{580} \\ x=(580)(0.454)=263.32
$

Answer: 263.3 yd

3 0

3 years ago

Consider −75/3. Which TWO statements are correct?

kiruha [24]

B.) the quotient is -25

3 0

3 years ago

Read 2 more answers

Please help very urgent

Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

2 years ago

Read 2 more answers