All dogs = 199999990158161231
2 answers:
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Answer:
The probability that at least one 5 will appear in 4 rolls of die equals
Explanation:
The given question can be solved by Bernoulli's trails which states that
If probablity of success of an event is 'p' then the probability that the event occurs at least once in 'n' successive trails equals
Since in our case the probability of getting 5 on roll of a die equals 1/6 thus we have p = 1/6
Applying the values in the given equation the probability of success in 4 rolls of die is thus given by
Answer:
Here is the method countPos
static int countPos(Scanner input){ //method that takes a reference to a Scanner object
int counter=0; // to count the positive integers
int number; //to store each integer value
if(input.hasNextInt()){ //checks if next token in this scanner input is an integer value
number=input.nextInt(); //nextInt() method of a Scanner object reads in a string of digits and converts them into an int type and stores it into number variable
counter=countPos(input); //calls method by passing the Scanner object and stores it in counter variable
if(number>0) //if the value is a positive number
counter++; } //adds 1 to the counter variable each time a positive input value is enountered
else { //if value is not a positive integer
return counter; } //returns the value of counter
return counter; } //returns the total count of the positive numbers
Explanation:
Here is the complete program:
import java.util.Scanner; //to take input from user
public class Main { //class name
//comments with each line of method below are given in Answer section
static int countPos(Scanner input){
int counter=0;
int number;
if(input.hasNextInt()){
number=input.nextInt();
counter=countPos(input);
if(number>0)
counter++; }
else {
return counter; }
return counter; }
public static void main(String[] args) { //start of main function
System.out.println("Number of positive integers: " + countPos(new Scanner(System.in))); } } //prints the number of positive integers by calling countPos method and passing Scanner object to it
The program uses hasNextInt method that returns the next token (next input value) and if condition checks using this method if the input value is an integer. nextInt() keeps scanning the next token of the input as an integer. If the input number is a positive number then the counter variable is incremented to 1 otherwise not. If the use enters anything other than an integer value then the program stops and returns the total number of positive integers input by the user. This technique is used in order to avoid using any loop. The program and its output is attached
