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Paha777 [63]
3 years ago
13

The read/write heads of a hard disk gently rest on the hard disk platters in order to read and write the data.

Computers and Technology
1 answer:
noname [10]3 years ago
6 0
The answer is FALSE because the interior of commercial Hard disk drive is with stack of magnetic disks (platters) containing the user’s data and a rotating arm supporting the magnetic heads. The rotating arm is moved by the torque generated by a voice coil motor (VCM) mounted at one end of the arm. Data read/write operations rely on the capability of the governing unit of the HDD to maintain the magnetic read/write heads as close as possible to center of the desired track. Typically, reliability of data reading and writing is guaranteed when the head is kept within 5% of the track pitch from the track center. This means that the accuracy required for the head positioning is in the range of a few tens of nanometers.
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NumA=2<br> for count range (5,8)<br> numA=numA+count <br> print(numA)
love history [14]

Answer:

for count in range (5,8): numA=numA+count print(numA)

Explanation:

7 0
3 years ago
Suppose we have two String objects and treat the characters in each string from beginning to end in the following way: With one
Simora [160]

Answer:

If all the character pairs match after processing both strings, one string in stack and the other in queue, then this means one string is the reverse of the other.                            

Explanation:

Lets take an example of two strings abc and cba which are reverse of each  other.

string1 = abc

string2 = cba

Now push the characters of string1 in stack. Stack is a LIFO (last in first out) data structure which means the character pushed in the last in stack is popped first.

Push abc each character on a stack in the following order.

c

b

a

Now add each character of string2 in queue. Queue is a FIFO (first in first out) data structure which means the character inserted first is removed first.

Insert cba each character on a stack in the following order.

a   b   c

First c is added to queue then b and then a.

Now lets pop one character from the stack and remove one character from queue and compare each pair of characters of both the strings to each other.

First from stack c is popped as per LIFO and c is removed from queue as per FIFO. Then these two characters are compared. They both match

c=c. Next b is popped from stack and b is removed from queue and these characters match too. At the end a is popped from the stack and a is removed from queue and they both are compared. They too match which shows that string1 and string2 which are reverse of each other are matched.

6 0
3 years ago
Case project 5-1 Network Integration ​
oee [108]

Answer:

You need to explain the entire network layout first.

Explanation:

Bringing on new IT Staff can be time consuming.  But depending on the possession you need to explain to them how the domain lay out is.  

4 0
3 years ago
Under the ____________________, federal agencies must 1) review their IT systems for privacy risks, 2) post privacy policies on
nadya68 [22]

Answer:

E-Government Act of 2002.

Explanation:

The E-Government Act of 2002 is a statute of the United States of America which was enacted by the 107th U.S Congress on the 17th of December, 2002. The E-Government Act of 2002 was signed into law to facilitate the management and promotion of the US government processes and services, as well as enhance transparency and accountability between the government and the public through the application of internet-based information technology.

Under the E-Government Act of 2002, federal agencies must;

1. Review their IT systems for privacy risks.

2. Post privacy policies on their websites.

3. Post machine-readable privacy policies on their websites.

4. Report privacy activities.

3 0
3 years ago
C++
Nookie1986 [14]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

class Window //defining a class Window

{

private:

int width, height;//defining integer variable

public:

friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters

{

return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values

}  

Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters  

{}

};

int main() //Main method

{

Window w(80,90);//calling class constructor

cout<<w;//print object value

return 0;

}

Output:

a (80 x 90) window

Explanation:

In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.

Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.

7 0
3 years ago
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