The answer is B! Ive past my test for this task.
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
1/4x^2+7x+2
Step-by-step explanation:
hope this helps
Answer:
the greatest common factor is 1.
Step-by-step explanation:
The factors of 3 are: 1, 3
The factors of 3 are: 1, 3
The factors of 4 are: 1, 2, 4
The factors of 5 are: 1, 5
The factors of 5 are: 1, 5
The factors of 17 are: 1, 17
Then the greatest common factor is 1.
