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telo118 [61]
3 years ago
9

What is 3(5x-6)+2(x+8)?

Mathematics
2 answers:
sdas [7]3 years ago
6 0

Answer:

D

Step-by-step explanation:

3(5x-6)+2(x+8)

=15x-18+2x+16

=15x+2x-18+16

=17x-2

Mashutka [201]3 years ago
4 0

Answer:

I believe it's D. 17x-2

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A certain pickup truck gets 20mpg in the city and 28 mpg on the highway. If the driver drives 270 mi on 11 gal of gas, determine
Snezhnost [94]

Answer:

95 city and 175 highway miles.

Step-by-step explanation:

The driver gets 20 mpg in city, and 28 mpg on the highway.

An equation that could be written is

20x+28y=270

This equation accounts for the distance traveled.

x+y=11

This equotion accounts for how many gallons were driven.

Multiply the bottom equation by 20, so you can solve the set of equations.

20x+28y=270

20x+20y=220

subtract them

8y=50

y=6.25

now plug this back into x+y=11

x+6.25=11

x=4.75

Now 4.75×20=95 city miles and 6.25×28=175 highway miles.

8 0
4 years ago
please help! 20 points. if you guess or just comment to take points i will make sure ur account gets banned, thanks! i want a si
alina1380 [7]

Answer: x=15

Step-by-step explanation: Since 3x+5 is equal to 50, you can write 3x+5=50, and 3x=45, x=15.

7 0
3 years ago
Which is a better buy, 4 lunches for $57 or 5 lunches for $71?
worty [1.4K]
Answer: 5 lunches for $71 is better
57/4=14.25
71/5=14.2
3 0
3 years ago
PLEASE HELP!! Write the equation of the graph.
Jet001 [13]
When you first look at thius graph, you should notice two things immedietly.

1. This graph will have a positive slope, because the line is going up.

2. the y-intercept is -2 because that's where it is on the y-axis.

Now, you have been given two points, (2, 1) and (0, -2). You can put these two points into the slope formula, which is: m = \frac{y2 - y1}{x2 - x1} \frac{(-2) - 1}{0 - 2} = \frac{3}{2} = 3/2.

So, now you have your slope and your y-intercept. Now, just put them into    y = mx + b form!

y = 3/2x - 2 (it is ubtracting two instead of adding two because it is a negative two.)

Hope this helps!!
~Kiwi
8 0
3 years ago
A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi
viktelen [127]

Answer:

Side length = \sqrt{\frac{A}{3} } cm ,   Height =  \frac{1}{2} \sqrt{\frac{A}{3} } cm  ,  Volume = \frac{A\sqrt{A}}{6\sqrt{3} }  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

  1. y = \frac{A - x^{2} }{4x}

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( \frac{A - x^{2} }{4x} )

V =  \frac{Ax - x^{3} }{4}

To find max volume put V' = 0

So taking derivative equation becomes

\frac{A - 3 x^{2} }{4} = 0

A = 3 x^{2}

x^{2} = \frac{A}{3}

x = \sqrt{\frac{A}{3\\} }

put value of x in equation 1

y = \frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }  

y = \frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }

y = \frac{1}{2} \sqrt{\frac{A}{3} }

So the volume will be

V = x^{2} × y

Put values of x and y from equation 2 & 3

V = \frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )

V = \frac{A\sqrt{A}}{6\sqrt{3} }

8 0
4 years ago
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