No more than 74 on average of 5 games means no more than 370 shots on total. If you add all of the numbers up you will get 292, so he can still shoot 370-292=78 in the last round, which is answer choice B.
F(3)=16 i saw this problem before so it should be the answer in the end
The degree of the polynomial will tell you the max amount of zeros you will have. 11 in this case.
However you can also have 9,7,5,3,1 (keep subtracting by 2)
So the answer is 1.
Answer:
If this is the problem
g(t) = t2 - 3t and h(t) = 3t - 4
g[ h(t) ] = (3t-4)2 - 3 (3t-4)
g[ h(t) ] = 9t2 - 24t + 16 - 9t + 12
g[ h(t) ] = 9t2 - 33t + 28
