Answer:
The radius of the circle 'r' = 5
Equation of the circle
(x - 2 )² + (y+1)² = (5)²
center of the circle ( h,k) = (2 , -1) , 'r' = 5
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given circle is x² - 4 x + y² + 2 y - 20 =0
x² - 2(2) x + (2)²-(2)²+ y² + 2 y(1) +(1)²-(1)² - 20 = 0
We know that
(a+b)² = a²+2 a b+b²
(a-b)² = a² -2 a b+b²
⇒(x - 2 )² - 4 + (y+1)² -21 =0
⇒ (x - 2 )² + (y+1)² = 25
<u><em>Step(ii):</em></u>-
Equation of the circle form
( x- h)² + (y -k)² = r²
Given circle (x - 2 )² + (y+1)² = (5)²
center of the circle ( h,k) = (2 , -1)
radius of the circle 'r' = 5
Answer:
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Step-by-step explanation:
Answer:
[-6, 8]
Step-by-step explanation:
Domain: set of all possible <u>input</u> values (x-values)
Range: set of all possible <u>output</u> values (y-values)
The <u>closed circles</u> on the <u>endpoints</u> of the curve mean that those points are <u>included</u> in the interval.
From inspection of the graph, the smallest y-value is -6 and greatest y-value is 8.
To express this in <u>interval notation</u> write the beginning and ending numbers of the interval inside <u>square brackets</u> as the end values are <u>included</u>.
(If the circles were open, and therefore the end values should not be included, use curved brackets).
Therefore the range of the given graph is: [-6, 8]
Answer:
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