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Masja [62]
3 years ago
7

Maya spent 40% of her savings on a bike it cost her $85 how much money does she have left

Mathematics
1 answer:
shusha [124]3 years ago
8 0
Let be Z the money ;
We have ( 40 / 100 ) x Z = $85 ;
( 4 / 10 ) x Z = $85 ;
( 2 / 5 ) x Z = $85 ;
Z = $( 85 x 5 ) ÷ 3 ;
Z = $425 ÷ 3 ;
Z = $141,66 ≈ $142 ;
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A book store sells a textbook for $150. If the textbook is on sale with 12% off, and there is a sales tax of 8.25% added to the
Yuri [45]

The textbook is $150 originally, so to find the price of the textbook on sale, multiply the original price by 12% (0.12). Then subtract 12% of 150 from 150.

  • 150 * 0.12 = 18

Subtract 18 from 150.

  • 150 - 18 = 132

Multiply the price of the textbook on sale by the sales tax of 8.25% (0.0825). Then add the tax price onto the sale price of the textbook.

  • 132 * 0.0825 = 10.89

Add 10.89 to 132.

  • 132 + 10.89 = 142.89

The final price of the textbook is $142.89.

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3 years ago
AE and DF are parallel. If √ABG = 11x and m_HCF = 10x + 9, what is m√ABG? 102° 99° 81° 9° ​
katrin [286]

Answer:

81

Step-by-step explanation:

6 0
3 years ago
Round 0.9874 to the greatest non zero place
Anna71 [15]
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5 0
3 years ago
Can you help with this?
g100num [7]

Answer:

c or d

Step-by-step explanation:

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3 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

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then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
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