\sqrt{(3\sqrt{2} -\sqrt{14} )^{2} } I am really having trouble with this, any pointers?
2 answers:
You might be interested in
Answer:
<h2>1.84feet</h2>Step-by-step explanation:
Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;
Range
U is the velocity of the arrow
H is the maximum height reached = distance below the bullseye reached by the arrow.
R is the horizontal distance covered i.e the distance of the target from the archer.
g is the acceleration due to gravity.
Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?
On substitution,
Squaring both sides we have;
The arrow will hit the target 1.84feet below the bullseye.