Answer: r = -11, q =3.5
Step-by-step explanation:
4q – 2r = 36 ....... eqn. 1
6q + r = 10 ..............eqn 2.
from eqn. 2 make r subject formula i.e.
r = 10- 6q (substitute for 'r' in eqn. 1)
we have;
4q - 2(10-6q) = 36 (open bracket)
4q -20 + 12q = 36 (collect like terms)
4q+12q = 36+20
16q = 56
q = 56/16
q = 3.5
substitute for q in eqn. 2.......
6(3.5) + r = 10
21 + r = 10
r = 10-21
r = -11, q =3.5
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Answer:
e=mc
Step-by-step explanation:
Answer:
r= -6
Step-by-step explanation:
<u>Assuming we are finding r,</u>
- | -2r-1| = 11
-( 2r + 1 ) = 11
-2r -1 = 11
-2r = 12
r= -6
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Answer: 26
Step-by-Step Explanation:
a = 10
b = 24
c = ?
Using Pythagoras Theorem,
c^2 = a^2 + b^2
c^2 = 10^2 + 24^2
c^2 = 100 + 576
c^2 = 676
=> c = √676 = 26
Hence, c = 26
Without a picture, it would be three linear pairs but to be more exact I would need a picture
hope this helps