First, open two separate terminal connections to the same machine, so that you can easily run something in one window and the ot
1 answer:
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Answer:
def insSort(arr):
ct=0;
for i in range(1, len(arr)):
key = arr[i]
j = i-1
while j >=0 and key < arr[j] :
arr[j+1] = arr[j]
j -= 1
ct=ct+1;
arr[j+1] = key
return arr,ct;
print(insSort([2,1]))
Output of the program is also attached.
Answer:
The flashdrive can hold 35389 400-pages-books
Explanation:
If of a page occupies 1 kB of memory, we can calculate how much memory a book will take
Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.
To do the calculation, we have to know how many kilobytes are in 9 gigabytes.
There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:
Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.
The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.