Which of these would be the fastest transition duration?
2 answers:
You might be interested in
Answer:
Here the code is given as follows,
Explanation:
Code:
import java.util.Scanner;
//created class named largeintegers
class largeintegers{
//class can hold a long number
long number;
//constructor to set number
largeintegers(long number){
this.number=number;
}
//getNumber method to get number
long getNumber(){
return number;
}
//below are some basic operations
long addition(long num1,long num2){
return num1+num2;
}
long subtract(long num1,long num2){
return num1-num2;
}
long multiply(long num1,long num2){
return num1*num2;
}
boolean compare(long num1,long num2)
{
return num1>num2;
}
public static void main(String[] args) {
//declared to long numbers
long number1,number2;
//scanner class to take user input
Scanner sc= new Scanner(System.in);
//taking input numbers
System.out.println("Enter a Number ");
number1=sc.nextLong();
System.out.println("Enter 2nd Number :");
number2=sc.nextLong();
//created two objects
largeintegers object=new largeintegers(number1);
largeintegers object2=new largeintegers(number2);
//displaying two numbers
System.out.println("Entered Numbers ");
System.out.println(object.getNumber());
System.out.println(object2.getNumber());
//calling basic methods using created objects
System.out.println("Some Operations on Given two Numbers ");
System.out.println("Addition:"+object.addition(object.getNumber(), object2.getNumber()));
System.out.println("Subtraction:"+object.subtract(object.getNumber(), object2.getNumber()));
System.out.println("Multiplication:"+object.multiply(object.getNumber(), object2.getNumber()));
System.out.println("Comparison:");
if(object.compare(object.getNumber(), object2.getNumber())==true)
{
System.out.println("First Number is Greater than Second Number ");
}
else
{
System.out.println("Second Number is Greater than First Number ");
}
sc.close();
}
}
Output:-
