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oksano4ka [1.4K]
3 years ago
6

Resumen sobres el correo electrónico​

Computers and Technology
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

Explanation:

El correo electrónico, también conocido como e-mail, es un servicio de red que permite mandar y recibir mensajes con múltiples destinatarios o receptores, situados en cualquier parte del mundo. Para usar este servicio se necesita cualquiera de los programas de correo electrónico que ofrece la red. Como outlook,g mail.

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What are the main features cyber law of Nepal​
muminat

Answer:

What are the provisions of cyber law in Nepal?

Provision of cyber law of NEPAL

It provides legal status to digital signatures and electronic records which in turn are used in electronic banking, shopping and commerce. It provides laws for formation of judicial system that operates only for crimes related to computer (internet and cyber space).

Hope this helps Have a good day

6 0
3 years ago
Write the statements needed so that the variable secondWord is associated with the second word of the value of sentence . So, if
professor190 [17]

Answer:

Explanation:

String str = "Broccoli is delicious.";

String[] Secondstr = str.split(" ");

System.out.println("second word is " + Secondstr[1]);

3 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
4 years ago
What are the two categories of problems that we can simply convert<br> to parallel code?
anastassius [24]
Percentage and decimals
7 0
3 years ago
I WILL MARK THE BRAINIEST!!!!!!!!!!!!! 50 POINTS!!!!!!!
Sauron [17]
Hello,

Your answer would be:

1. It’s important to have a good study skill so you can be ready to take a quiz such as world history.

2. It’s important to know your time on tasks because you don’t want to spend all day on one simple task you want to get things done.

3. A schedule can help you get organzied because it helps you with your time such as this go along with your second question.

Have a nice day :)

~Rendorforestmusic
5 0
4 years ago
Read 2 more answers
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