Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
Step 1: Find the Lowest Common Multiple between the denominators.
Step 2: Multiply the numerator and denominator of each fraction by a number (the one that will get them to the lcm) so that they have the LCM as their new denominator.
Step 3: Add or subtract the numerators and keep the denominator the same.
Answer:
A) x = 20
Step-by-step explanation:
ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.
Since, diagonals of a rhombus are perpendicular bisector.
Answer:
Maria needs 3 lengths of gutter of finish the shed.
Step-by-step explanation:
We need to calculate the perimeter of the rectangular shed to know how much 5 feet gutter is needed.
The perimeter of the shed is p = 2(l + b) where l = 10ft and b = 9 ft
p = 2(10 + 9) = 2(19) = 38 ft
Now, the perimeter of the shed also equal 23 ft of gutter already installed plus 5x ft gutter where x = number of gutters.
So 23 + 5x = 38
collecting like terms, we have
5x = 38 - 23
5x = 15
dividing through by 5 we have
5x/5 = 15/5
x = 15/5
x = 3
So, Maria needs 3 lengths of gutter of finish the shed.
Answer:
(y+10)/5
Step-by-step explanation:
You start off by adding 10 on both sides cancelling the 10 on the right side and you get y+10=5x. From there you then divide by 5 on both sides and you get your answer of (y+10)/5.
