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levacccp [35]
2 years ago
6

In the general population, the mean IQ is 100 with a standard deviation of 15. Dr. Robbins wants to see if a class of statistics

students is significantly smarter than the population, so Dr. Robbins gives them an IQ test to get the average IQ of the students. To test the theory that Stats in Psych students are smarter than the general population, which hypothesis test is appropriate
Mathematics
1 answer:
Shalnov [3]2 years ago
7 0

From the information given, a right-tailed test using the z-distribution is appropriate.

At the null hypothesis, it is <u>tested if the class of statistics students is not significantly smarter than the general population</u>, that is, their mean IQ is of at most 100, hence:

H_0: \mu \leq 100

At the alternative hypothesis, it is <u>tested if they are significantly smarter</u>, that is, their mean IQ is greater than 100, hence:

H_1: \mu > 100

  • We are testing if the mean is <u>greater than a value</u>, hence it is a right-tailed test.
  • We have the <u>standard deviation for the population</u>, hence, the z-distribution is used.

A similar problem is given at brainly.com/question/23413408

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Answer:

B,C,D

Step-by-step explanation:

24ft =288 in A IS FALSE

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1/2 miles = 2640 ft C IS TRUE

0.5 miles = 880 Yds D IS TRUE

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Why is this simplified by combining like terms <br> 3(4x+5) +2
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3(4x+5)+2
3•4x=12x
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M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
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