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Reil [10]
4 years ago
5

The pic is the question! Please help

Mathematics
2 answers:
bulgar [2K]4 years ago
4 0

Answer:

93 is your correct answer

Step-by-step explanation:

kirza4 [7]4 years ago
3 0

Answer:

93

Step-by-step explanation:

150×62%

150×62/100

15×62/10

=930/10

=93

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if a number is increased by 100%, how does the increased number compare with the original number? explain​
Harrizon [31]
Through common sense a number is already at it’s 100%. And so by increasing The percentage of the number you are also increasing the number itself.

For example take the number 10. If you increase it by 20% you'll take 2 out of 10 and add it to original number which will result in 12, 20% more or 120% in total. And so if you apply the same situation but with a hundred percent, you will double the number and get a number of 20 or 200%. An increase of a 100% plus the original 100%. If this doesn't make sense however, I'm sorry as my "explaining" skills suck
8 0
3 years ago
What is the difference of 31 - (-9) =
Licemer1 [7]

Answer:

40

Step-by-step explanation:

31 + 9=40

cause u need to change the negative into positve and change the minus into plus

5 0
3 years ago
99(100x)+31=89 what is the answer to this problem
Maslowich
<span>99(100x)+31=89
=> 9900x + 31 =89
=> 9900x = 89 - 31=58
=> x = 58/9900

Hope it helps !!!</span>
8 0
4 years ago
Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust is a Poisson random variable with a me
Maslowich

Answer:

The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357

Step-by-step explanation:

For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.

We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by

W = \frac{X-\mu}{\sigma} = \frac{X-10000}{100}

We have

P(X>10110) = P(\frac{X-10000}{100} > \frac{10110-10000}{100}) = P(W > 1,1) = 1-\phi(1,1) = 1-0.8643 = 0.1357

Where \phi is the cummulative distribution function of a standard normal distribution. The values of \phi are well known and they can be found in the attached file.

We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.

Download pdf
4 0
3 years ago
Can anyone help me with this I don't understand this please help me
I am Lyosha [343]
1. It's asking if the hourly pay seems linear or nonlinear. Which is practically you just giving one or the other.

2. It's asking where the number cluster close together. Which is from 4-6

Those are the only 2 I see difficult to understand
3 0
4 years ago
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