suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
$24.84
Step-by-step explanation:
i did the work lol
give brainliest please
Craming last minute can lead to unecessary confusion however most examinars dont allow asking questions during exam
So if asking questions for clarification is allowed. A) is the odd one out
And these options are rather for test taking than learning
Answer:
The distance flown
Step-by-step explanation:
The distance flown is dependent on the speed of the plane
Think these are the answers to the first few hope it helps