Lightly draw a vertical line at -3 (x= -3 is the divider) on the left side graph x + 1, on the right side graph 1/2x + 2.
because these equations don't match up at the -3 coordinate, you have to draw an open (not colored in) circle at the beginning at the 1/2x-2 equation
We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
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I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
hgktjeghuegkekhghkegkhetgkhekhjhkjeg
Step-by-step explanation:
Answer:
false
Step-by-step explanation:
false , because A is between C and B , it must be on the same straight line
Answer:
Option A
Step-by-step explanation:
since V = p×r^2×h
r = 3/2
hence, option a is correct.
