The probability of drawing two blue marbles if the first marble is not replaced is 1/5
<h3>How to determine the probabilities?</h3>
<u>The probability of tossing a head and drawing a red marble</u>
The given parameters are:
White = 1
Blue =3
Red = 2
Total = 6
The probability of a head is
P(Head)= 1/2
The probability of drawing a red marble is
P(Red)= 2/6 = 1/3
The required probability is
P = P(Head) * P(Red)
This gives
P = 1/2 * 1/3
P =1/6
<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>
Here, we have:
P(B1) = 3/6 = 1/2
P(B2) = 2/5
The required probability is
P = P(B1) * P(B2)
This gives
P = 1/2 * 2/5
P =1/5
Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5
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Answer:
c
Step-by-step explanation:
c is always a good guess
Answer: 11
step by step instructions: so you have your statement. (3/7)r+(5/8)s you then would plug in (14) for (r) and (8) for (s).once you plug these in you then simplify the statement. (3/7)*14=6 and (5/8)*8=5. so your new statement should be 6+5=11
hope this helps
<h2>(THIS ANSWER WAS DELTED FROM BRAINLY.COM)</h2><h2 /><h3>Stated by Brainly Headquarters inc.</h3><h3>2-19-21</h3>
