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zubka84 [21]
3 years ago
14

1-tanA÷1+tanA=1-sin2A÷cos2A​

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

hope u get it. I've used RHS to prove LHS

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Solve the inequality 5x7 < 2x - 1
Vanyuwa [196]

x is strictly less than 2 or x ∈ (-∞, 2)

Given: inequality 5x - 7 < 2x - 1

What are inequalities?

Inequalities are statements that are represented as comparison between two or more numbers or algebraic expressions.(strictly less, strictly great, greater, lesser)

Solving the given equation:

5x - 7 < 2x - 1

=> 5x - 7 - 2x < 2x - 1 - 2x

=> 3x - 7 < -1

=> 3x - 7 + 7 < -1 + 7

=> 3x < 6

=> x < 2

Therefore, x is strictly less than 2.

Hence x ∈ (-∞, 2)

The number line is attached below.                      

Know more about "inequalities" here: brainly.com/question/20383699

#SPJ9

Disclaimer: The given question is incomplete. The complete question is given below.

Solve the inequality 5x - 7 < 2x - 1

On the number line, represent the solution

(number line -5 to 5)​

5 0
2 years ago
What is the perimeter of the figure to the nearest hundredth?
VikaD [51]

Answer:

perimeter=50.26

Step-by-step explanation:

(9*3.14)=28.26

28.26+5+5+12=50.26

6 0
3 years ago
5/16÷(-)=-45/18 plz answer​
Alina [70]

Answer:

x= -1/8

Step-by-step explanation:

5/16 ÷ x = -45/18

⇒x= (5/16)÷(-45/18)

⇒x= -1/8

7 0
3 years ago
What is the solution to the inequality? 4x−5&gt;19−8x
Nostrana [21]

Answer:

x>1.16

Step-by-step explanation:

Subtract 5 from each side to get 4x>14-8x

change the symbol from +8 to -8

4x> 14+ (-8x)

than add 8x to both sides

12x > 14

which would mean that x has to be greater than 1.16

x>1.16

7 0
3 years ago
20 points, please help within 20 minutes.
RoseWind [281]

Answer:

C, the biggest triangle with its vertices at (0,5) and (10,0).

Step-by-step explanation:

I will refer to the 2nd image's triangle as A, the 3rd as B, and the 4th as C.

First, let's look at the original triangle. Two of its vertices are at (0,3) and (6,0).

Now, let's look at A. Two of its vertices are at (0,3) and (9,0). One of the vertices is in the same location, aka (0,3), as the original triangle. A proper dilation would have increased the lengths of all sides of the triangle, so this can't be the right answer.

B is obviously much smaller than the original triangle, so we can take one look at it and know that it is not the correct answer because the problem specifies that the original triangle was dilated by a scale factor GREATER than 1, aka the dilated triangle would have to be bigger than the original. So, this is wrong, too.

This leaves us with C. It is dilated to a size bigger than the original, and each side length was dilated, so I think it is safe to assume that this is the correct answer.

Hopefully this helped, and if I was correct, I'd appreciate it if you marked me as the Brainliest :)

7 0
3 years ago
Read 2 more answers
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