Answer:
There's two answers.
-5, -4, and -3
3, 4, 5
Step-by-step explanation:
Mr. Juarez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. Th
1 answer:
Answer:
$576.80
Step-by-step explanation:
We have been given that Mr. Juárez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. The account earns 1% simple interest.
We are asked to find the total amount that Mr. Juárez will have in his account at the end of 3 years.
We will use simple interest formula to solve our given problem.
A = Final amount after t years,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
Let us convert 1% into decimal form,
1%=1/100=0.01
P=$560 and t=3
A=$560 (1+0.01(3))
A=$560 (1+0.03)
A= $560 (1.03)
A= $576.80
Therefore, Mr. Juárez will have $576. 80 in his account at the end of 3 years. Hope this helps!
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If AM=BM, then point M is a middle point of side AB.
1. Consider triangle AML. You know that AM=ML, then this triangle is isosceles and AL is its base. The angles adjacent to the base of isosceles triangle are conruent, this means that
2. Consider lines ML and AC. The angle bisector AL is transversal. Since alternate interior angles you have that lines ML and AC are parallel. This means that ML is a middle line of triangle and 2ML=AC. Also you know that AC=2AL. This gives you that ML=AL. Now ML=AL and ML=AM gives you that triangle AML is equilateral.
3. In equilateral triangle AML all angles are congruent and have measures 60°. Thus, m∠AML=m∠MLA=m∠LAM=60°.
4. AL is angle bisector, then m∠MAL=m∠LAC=60° and m∠BAC=m∠MAL+m∠LAC=120°.
5. Consider ΔBML, it is isosceles, because BM=ML and m∠BML=180°-m∠AML=180°-60°=120°. Then,
6. Consider triangle ABC. In this triangle m∠A=120°, m∠B=30°, then
m∠C=180°-m∠A-m∠B=180°-120°-30°=30°.
Answer: m∠A=120°, m∠B=m∠C=30°.
Answer:
Step-by-step explanation:
The similar triangles are drawn in the figure attached.
As shown in the figure, the smaller triangle ΔABC, and the larger triangle ΔA'B'C' share the same slope; therefore, the slope of the hypotenuse is the length of the triangle ΔA'B'C' divided by its base:
Therefore, the equation of the hypotenuse is
