Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Answer:
10.3cm
Step-by-step explanation:
h=A
b=131.84
12.8≈10.3cm
The answer would be -4 because you are dividing by -5
I'm pretty sure it's: 5x + 2y = –14
Answer:
jwjeek
Step-by-step explanation:
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