Enter the value that belongs in the<br> green box

Triangle ABC has sides with lengths of 11, 18, and 8 units. Determine whether this triangle is a right triangle.

Arturiano [62]

Answer:

Not a right triangle.

Step-by-step explanation:

If this triangle is a right triangle, then the Pythagorean theorem would work on it. According to the Pythagorean theorem, $a^2+b^2=c^2$ , so c would always be greater than a or b. In this scenario, the greatest number here is 18, so c = 18. Since a or b don't matter if given both legs, we have the following equation that may or may not be equal: $8^2+11^2=18^2$ . We know 8 squared is 64, and 11 squared is 121, and 18 squared is 324. This means that $64+121=324$ according to the Pythagorean theorem, and since 64 + 121 = 185, and 185 does not equal 324, the Pythagorean theorem does not work and the triangle is not a right triangle.

3 0

3 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

Help me with A and B please

g100num [7]

Part A.

Ashwin had a 4-cm cube.

volume of cube = side^3

volume = (4 cm)^3 = 64 cm^3

Ashwin has 64 small cubes.

We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.

A. v = 2 * 4 * 7 = 28

B. v = 4 * 5 * 6 = 120

C. v = 5 * 5 * 4 = 100

D. v = 4 * 7 * 5 = 140

E. v = 3 * 5 * 4 = 60

Part A. answer: A, E

Part B.

Dora had a 5-cm cube.

volume of cube = side^3

volume = (5 cm)^3 = 125 cm^3

Dora has 125 small cubes.

We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.

A. v = 3 * 3 * 8 = 72

B. v = 3 * 4 * 5 = 60

C. v = 6 * 6 * 4 = 144

D. v = 5 * 8 * 4 = 160

E. v = 3 * 5 * 4 = 60

Part B. answer: A, B, E

6 0

3 years ago

Lol again another math solver help pls! LOL

gladu [14]

Answer:

b = 4

Step-by-step explanation:

5-1=5b-4b

4=b

4 0

3 years ago

Read 2 more answers

What is the value of 10+/-3-6/

garri49 [273]

Answer:

18

Step-by-step explanation:

-3-6= -8 but since its absolute value it'll be 8 so 8 plus 10 = 18

7 0

4 years ago

Enter the value that belongs in the green box