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Andreyy89
3 years ago
10

16. For quadrilateral ABCD, determine the most precise name for it. A(2,3), B (12,3), C(8,6) and D(5,6). Show your work and expl

ain.
Mathematics
1 answer:
maw [93]3 years ago
6 0
The correct answer is a Trapezoid.
First, I drew and labeled the points on a graph. When these points are connected, you can see that the space between DA and CB is not equal, meaning that the trapezoid is not isosceles.
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How do I slove 4/5 - 8/15
Reika [66]
The answer is 4/15, because we have to get the denominaters to be the same, so the LCM of 5 and 15 is 15, so 15/5 is 3 and 4*3 is 12. Now, its 12/15-8/15 which is 4/15. Hope this helps!

6 0
2 years ago
What is the domain of y=(x+5)(x-2)(x-7)
gavmur [86]
The correct answer is 16
6 0
3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
Given that cosA = -8/17  and sinA is negative, determine the value of tanA.​
borishaifa [10]

Answer:

tan A = -15/8.

Step-by-step explanation:

sin^2a = 1 - cos^2A

= 1 - (-8/17)^2

= 225/289

So sin A= 15/17

tan A = sin A / cos A

=  15/17 / -8/17

= 15/-8

= -15/8.

5 0
3 years ago
Please help me with these questions
Jlenok [28]
Posted 5 days ago no need for an answer now.

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3 years ago
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