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leva [86]
3 years ago
7

Fine the Value of x. Can someone help me plz???

Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

pretty sure its 37

Step-by-step explanation:

check on a calculator first

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Graph the equation on the coordinate plane y= -3/4+1
musickatia [10]

Answer:

OMG IS THAT PROBABILITY ON A GRAPH THOUGH PLEASE REPLY SO I COULD ANSWER...

Step-by-step explanation:

6 0
3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
. Ashton was asked to write an equation in the form y = mx + b for the line shown in the graph below. ATT 4 He wrote the equatio
tamaranim1 [39]

Answer:B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
3a+4b= c solve for b
Alina [70]

Answer:

b = (c - 3a)/4

Step-by-step explanation:

3a + 4b = c

4b = c - 3a

b = (c - 3a)/4

6 0
2 years ago
a company makes carboard cylindrical boxes with a diameter of 10 inches and a height of 8 inches.how many square inches of carbo
NeTakaya

Answer:

408.2sq inches

Step-by-step explanation:

Area of the cylindrical box = 2πr(r+h)

r is the radius  = diameter/2

r = 10/2 = 5in

h is the height = 8in

Substitute

Area of the cylindrical box  = 2(3.14)(5)(5+8)

Area of the cylindrical box = 2 * 3.14 * 5 * 13

Area of the cylindrical box  = 408.2sq inches

8 0
3 years ago
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