Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,
Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then
Take positive value x. You get
2. According to the previous theorem,
Then
Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then
This means that you cannot find solutions of this equation. Then CD≠2 cm.
Answer: Option a.
Step-by-step explanation:
Make the denominator equal to zero and solve for x:
Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:
Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2
The answer is the option a.
Answer:
$15
Step-by-step explanation:
To figure thsi out, you do 20 divided by 8, which gives you 2.5 ($2.50.)
Next you do 2.50 x 6 which gives you 15 ($15.)
The answer is $15.
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Answer:
Perimeter of a square=circumference of circle
4×22=2πr
44=πr
r=14
Area of circle=πr2
22/7×14×14
28×22
616
