All categories

3 years ago

1.

Mathematics

1 answer:

STALIN [3.7K]3 years ago

3 0

Answer: I'm pretty sure it's 25

Step-by-step explanation:

Use Pythagorean theorem to find diagonal.

You might be interested in

I WILL GIVE BRAINLIEST to who answers this question right

nydimaria [60]

Answer:

41 2/3 feet

Step-by-step explanation:

The sum of wall lengths (in feet) is ...

(12 1/4) + (10) + (12 1/4) + (10 -2 5/6)

= (12 + 10 + 12 + 8) + (1/4 + 1/4 - 5/6)

= 42 + (3/12 + 3/12 -10/12)

= 42 - 4/12 = 42 - 1/3

= 41 2/3 . . . feet

7 0

4 years ago

Help me asap pleaseeeeee

34kurt

Answer:

1. her elevation at noon was 3 meters

2. (-2, 7)

3. (1, 0)

Step-by-step explanation:

1. when x = 0, it is noon, y = 3 when x is 7

2. when x = -2 it is 10 am because when x is 0, it is noon, or 12 pm, her elevation is 7 meters above sea level

3. when x is 1, it is 1 pm, and her elevation is 0 meters

5 0

3 years ago

If you are told to calculate simple interest, and you are told to calculate the interest for 6 months, what would you need to do

Sophie [7]

Answer:

number of periods per year m, times the number of periods n: simple interest amount = principal amount × (rate / m) × n.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

3. sin t + cos2 t / sin t =

Charra [1.4K]

See the picture, please!!

7 0

3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago