The answer to 2y+7(y-3)=60 is y=9
Answer:
$1756
Step-by-step explanation:
1. More = Addition
2. Twice = Multiplication by 2
3. Tuition costs $100 more than twice room and board
Tuition = 2x + 100
$2584 = (2x + 100) + x
$2584 = 3x + 100
4. Subtract 100 on both sides: $2484 = 3x
5. Divide both sides by 3: $828 = x
6. Plug it in to the tuition equation: Tuition = 2(828) + 100
= $1756
Check Work: (828*2) + 100 = $1756
$1756 + 828 = $2584
{(–1, 1), (–2, 1), (–2, 2), (0, 2)}
In a function, each input has an output
Each domain has a range. In a function, range can be repeated but domain cannot be repeated. Same domain cannot have two range values.
Here domain is {-1, -2, -2, 0}
Range is { 1, 1, 2, 2}
Domain -2 is repeating so this relation is not a function
Answer : No; a domain value has two range values.
Answer:
x = 181 and y = 97
Step-by-step explanation:
let called the first number is x
the second number would be called y
We are given that:
x + y = 278 (1)
x = y + 84 (2)
Let change x in (2) into (1):
y + 84 + y = 278
2y + 84 = 278
Subtract 84 from both side, we got:
2y + 84 - 84 = 278 - 84
2y + 0 = 194
Divide both side by 2, we got:
2y / 2 = 194 / 2
y = 97
Because y = 97 and x + y = 278 so x would equal:
x + 97 = 278
Subtract 97 from both side, we got:
x + 97 - 97 = 278 - 97
x + 0 = 181
x = 181 and y = 97
Hope this helped :3
If you graph the end points C and D then graph the 4 points at the end it is difficult to tell which points are on CD without a line.
Using the endpoints find the slope (change in y/ change in x) then substitute a point in to find the intercept.
Slope = (-6-4)/(6- -8) = -5/7
Intercept equation (-6) = -5/7 (6) + b
b = -1.71428571429
Graphing the line shows only 2 points on the line (–2.75, 0.25) and <span>(0.75, –2.25)
I am confused by the part, "</span><span>P is the length of the line segment from D". Were you given a length P to help you determine which point. Using the distance formula to find the length from each point to D doesn't help determine which one is best with the information you have given. The image shows the distances I calculated and the graphed points.
I hope this helps!</span>