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icang [17]
3 years ago
11

3/4 x 1/8 in simples form

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0

Answer:

3/32

Step-by-step explanation:

To get this answer, multiply the numerators together and the denominators together

3x1=3

4x8=32

3/32

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Step-by-step explanation:

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Quadrilateral FRIO is the result of a reflection of quadrilateral LAMB over the y-axis. FRIO has vertices at F(-7,6), R(1,7), I(
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Answer:

F' = (7, 6)

R' = (-1, 7)

I' = (-2, -5)

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Step-by-step explanation:

The rule of reflection over the y-axis is, (x, y) ---> (-x, y). So change all the x values into the opposite signs. So the -7 of F would turn into just 7, the 1 of R would turn into -1, the 2 of I would turn into -2, and -6 of O would turn into just 6.

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4 years ago
g You plan to construct a confidence interval for the mean μ μ of a Normal population with known standard deviation σ . σ. Which
muminat

Answer:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can reduce this margin of error with:

Increasing the sample size

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

The margin of error is given by:

[tex] ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can reduce this margin of error with:

Increasing the sample size

5 0
3 years ago
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