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vladimir2022 [97]
3 years ago
10

What are the solutions of 3(x - 4)(2x - 3) = 0? Check all that apply.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

4 and 3/2

Step-by-step explanation:

x = 4

2x = 3 \\ x =  \frac{3}{2}

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I need help on this 2 problems please help​
Digiron [165]

Answer:

3. 294 m²

4. 185,856 mm²

Step-by-step explanation:

To find the surface area of any figure, you can simply find the sum of the areas of all the sides.  In question 3, the figure is a triangular prism that has two triangular bases and three rectangular sides.  The measurements for the triangles are b = 9m and h = 6m.  The formula for the area of a triangle is base times height divided by 2, or 9 x 6 = 54/2 = 27 m². However, since there are two triangular bases, the area for both is 54 m².  The measurements for the other three rectangles are given:

7(10) + 8(10) + 9(10) = 240 m² + 54 m² = 294 m²

The surface area of a cube is much easier since all sides are equal and can be found using the formula:

SA = 6s², where 's' represents the measure of a side.

SA = 6(176)² = 185,856 mm²

6 0
3 years ago
In Joe's fish tank, there are 5 goldfish and 9 snails. How does the ratio 9:14 describe Joe's fish tank?
Natalija [7]
The answer is C, number of snails to the total number of animals
4 0
2 years ago
1/24+4/5 divided be 3/5
Sindrei [870]

Answer:

1.375

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
MARKING BRAINLIEST PLZ HURRY<br><br> 1 1/4 + ? = 0
Rzqust [24]

Answer:

? = -1 1/4 (Negetive one and one fourth)

Step-by-step explanation:

Use this calculator to solve those difficult Algebra problems!

https://www.mathpapa.com/algebra-calculator.html

8 0
3 years ago
WILL GIVE BRAINLIEST write an equation for the nth term of the arithmetic sequence and find the 30th term 28, 25, 22, 19, ... (s
Fudgin [204]

Answer:

a_n = 31 - 3n\\\\a_{30}= 59

Step-by-step explanation:

Given Arithmetic sequence is:

28, 25, 22, 19, ...

a = 28, d = 25 - 28 = - 3,

nth term of an Arithmetic sequence is given as:

a_n = a + (n - 1) d\\

Plugging a = 28 & d = - 3 in the above equation, we find:

a_n = 28 + (n - 1) (-3)\\\\a_n = 28 - 3n +3\\\\\huge\purple {\boxed {a_n = 31 - 3n}} \\(This \:is \:the \:required \:equation) \\\\Plug \: n = 30, \: we \: find:\\\\a_{30}= 31 - 3 \times 30\\\\a_{30}= 31 - 90\\\\\huge\orange {\boxed {a_{30}= 59}} \\\\

7 0
3 years ago
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