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3 years ago

What are the solutions of 3(x - 4)(2x - 3) = 0? Check all that apply.

Mathematics

1 answer:

11111nata11111 [884]3 years ago

3 0

Answer:

4 and 3/2

Step-by-step explanation:

$x = 4$

$2x = 3 \\ x = \frac{3}{2}$

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If x/y + y/x = -1 , find the value of x^3 - y^3

marin [14]

Answer:

Step-by-step explanation:

Multiplying the first equation by xy, we have ...

x^2 +y^2 = -xy

Factoring the expression of interest, we have ...

x^3 -y^3 = (x -y)(x^2 +xy +y^2)

Substituting for xy using the first expression we found, this is ...

x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0

The value of x^3 -y^3 is 0.

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3 years ago

Which expression is equivalent to n+n+n? A. 3^n B. 3n C. n^3 D. n+3

Irina18 [472]

Answer:

B. 3n

Step-by-step explanation:

n + n + n = 3n

------------------------------------------

3n = n + n + n

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2 years ago

I need you show me the answer what a or b or c

AlladinOne [14]

That would be A, its the only on where all the dots line with the numbers given

5 0

4 years ago

Read 2 more answers

A particle sits on a smooth surface and is acted upon by a time dependent horizontal force, giving it an

garik1379 [7]

(a) By the fundamental theorem of calculus,

v(t) = v(0) + ∫₀ᵗ a(u) du

The particle starts at rest, so v(0) = 0. Computing the integral gives

v(t) = [2/3 u ³ + 2u ²]₀ᵗ = 2/3 t ³ + 2t ²

(b) Use the FTC again, but this time you want the distance, which means you need to integrate the speed of the particle, i.e. the absolute value of v(t). Fortunately, for t ≥ 0, we have v(t) ≥ 0 and |v(t) | = v(t), so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of

∫₀⁸ v(u) du = ∫₀⁸ (2/3 u ³ + 2u ²) du = [1/6 u ⁴ + 2/3 u ³]₀⁸ = 1024

7 0

3 years ago

1. Are the following triangles similar? Justify your answer.

DerKrebs [107]

Answer:

no they are not similar. this is because figure MCD had no corresponding sides to figure NLO. The two figures are not congruent or similar

5 0

3 years ago