What is the equation of a line perpendicular to why=2x-6 that passes through (5,4)
1 answer:
Answer:
y = ½(13- x)
Step-by-step explanation:
Step 1. Find the<em> slope (m₁) of the original line </em>
The equation for the original line is
y = 2x - 6
slope = m₁ = 2
Step 2. Find the <em>slope (m₂) of the perpendicular line </em>
m₂ = -1/m₁ Substitute the value of m₁
m₂ = -1/2
Step 3. Find the <em>equation for the perpendicular line</em>
y = mx + b Substitute the value of m₂
y = -½x + b
The line passes through (5, 4).
4 = -½(5) + b Add 5/2 to each side
4 = -5/2 + b Add 2 to each side
b = 13/2
y = -½x + 13/2
y = ½(13 – x)
In the image, below, the red line is the graph of your original equation.
The blue line passing through (5, 4) is the perpendicular line.
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Answer:
y = 17x-67
Step-by-step explanation:
The one point form of line also called slope point form is given by
where (x1, y1) is the point and m is slope
Given: (x1, y1) = (4,1) and m= 17
Substituting these values in above equation to find equation in point-slope form
(y-1)=17(x-4)
y-1 = 17x-68
y = 17x-67
the point -slope form of equation y = 17x-67
Answer:
The answer is below
Step-by-step explanation:
The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.
Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.
The loan must be at least for 5.72 years for an annual interest rate (r) of 10%