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What is the equation of a line perpendicular to why=2x-6 that passes through (5,4)
1 answer:
Answer:
y = ½(13- x)
Step-by-step explanation:
Step 1. Find the<em> slope (m₁) of the original line </em>
The equation for the original line is
y = 2x - 6
slope = m₁ = 2
Step 2. Find the <em>slope (m₂) of the perpendicular line </em>
m₂ = -1/m₁ Substitute the value of m₁
m₂ = -1/2
Step 3. Find the <em>equation for the perpendicular line</em>
y = mx + b Substitute the value of m₂
y = -½x + b
The line passes through (5, 4).
4 = -½(5) + b Add 5/2 to each side
4 = -5/2 + b Add 2 to each side
b = 13/2
y = -½x + 13/2
y = ½(13 – x)
In the image, below, the red line is the graph of your original equation.
The blue line passing through (5, 4) is the perpendicular line.
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Answer:
y = x²/4 + x/2 + 21/4 ⇒ -9 ≤ x ≤ 7
Step-by-step explanation:
∵ x = 2t - 1
∴ 2t = x + 1 ⇒ t = (x + 1)/2
∵ y = t² + 5
∴ y = [(x + 1)/2]² + 5 = (x² + 2x + 1)/4 + 5
y = x²/4 + x/2 + 1/4 + 5 = x²/4 + x/2 + 21/4
∵ -4 ≤ t ≤ 4
∴ -9 ≤ x ≤ 7
