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8090 [49]
3 years ago
13

Which variable expression represents the word phrase?

Mathematics
2 answers:
zhuklara [117]3 years ago
3 0
I believe it is A.) 4 + (y / 11)
Nesterboy [21]3 years ago
3 0

Answer: A.) 4 + (y / 11)


Step-by-step explanation: i took the test:>)


You might be interested in
If y varies with x, and y=-20 and x=5, what is x when y=-30?
vladimir1956 [14]

If y = -30, then x = 7.5

Hope this helps.

3 0
3 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
Which set of points represents a function?
Greeley [361]

Answer:

the 0,2 does beautiful as it comes

4 0
3 years ago
Hiow do you solve 3+3j=10+3j
vodomira [7]
No solution! Hope this helped
6 0
3 years ago
A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of
Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

m=\frac{y2-y1}{x2-x1}

m=2

so

2=\frac{y2-y1}{x2-x1}  -----> equation A

x2=x1+3.5 ----> equation B

substitute equation B in equation A

2=\frac{y2-y1}{x1+3.5-x1}  

2=\frac{y2-y1}{3.5}  

7=y2-y1  

y2=y1+7  

therefore

The ordinate of B exceeds the ordinate of A by 7

6 0
3 years ago
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