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Liono4ka [1.6K]
3 years ago
13

Five submarines sink on the same day, and all five go down at the same spot where a sixth had previously sunk. How might they al

l lie at rest so that each submarine touches the other five? To simplify, arrange six wooden matches so that each match touches every other match. No bending or breaking allowed.

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

Answer:

picture is attached

Step-by-step explanation:

there are many options but this is one

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Use inductive reasoning to predict the most probable next number in each list.
PolarNik [594]

Answer:

  93

Step-by-step explanation:

First differences increase by 4 each time. The given numbers are a quadratic sequence that can be described by 2n² -2n +9. The 7th term would be 93.

_____

First differences are ...

  13-9 = 4, 21-13 = 8, 33-21 = 12, 49-33 = 16, 69-49 = 20

Second differences are ...

  8-4 = 4, 12-8 = 4, 16-12 = 4, 20-16 = 4

When second differences are constant, the sequence can be represented by a second-degree polynomial function. The leading coefficient is half the value of the second differences.

3 0
3 years ago
Oscar has received a $4,000 gift and is looking for a bank to start a savings account. Which option would be the best for him at
Brut [27]

Here is the complete question

A nominal interest rate of 5%

A real interest rate of 5%

A real interest rate of 3%

A nominal interest rate of 3%

Answer:

A real interest rate of 5%

Step-by-step explanation:

A real interest rate of 5% is the best option for oscar. The nominal rate of interest is a type of interest rate that shows the increase in in percentage of money without the depreciation discount that is usually caused by inflation or the payment of tax.

The real rate of interest shows the real increase in the money that has been paid for an investment. This is after inflation has been discounted and all forms of taxes have been paid.

So oscar should invest his $4000 on a savings account whose real interest rate is 5% per year

6 0
4 years ago
I need to combine and simplify this radical expression but forgot how... please help
steposvetlana [31]
\bf \cfrac{1}{3}\sqrt[3]{81}\implies \cfrac{1}{3}\sqrt[3]{3^4}\implies \cfrac{1}{3}\sqrt[3]{3^{3+1}}\implies \cfrac{1}{3}\sqrt[3]{3^3\cdot 3^1}\implies \cfrac{1}{3}\cdot 3\sqrt[3]{3^1}
\\\\\\
\sqrt[3]{3}
5 0
3 years ago
A Common Measure of Student Achievement, The National Assessment of Educational Progress (NAEP) is the only assessment that meas
vlada-n [284]

Answer:

a) By the central limit theorem we know that if the random variable X="quantitative scores for young women", and we know that this distribution is normal.

X \sim N(\mu, \sigma=60)

And we are interested on the distribution for the sample mean \bar X, we know that distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And with that we have the assumptions required to apply the normal distribution to create the confidence interval since the distribution for \bar X is normal.

b) 270.283\leq \mu \leq 279.717

c) We are confident (99%) that the true mean for the quantitative scores for young women is between (270.283;3279.717)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=275 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=60 represent the population standard deviation

n=1077 represent the sample size  

Part a

By the central limit theorem we know that if the random variable X="quantitative scores for young women", and we know that this distribution is normal.

X \sim N(\mu, \sigma=60)

And we are interested on the distribution for the sample mean \bar X, we know that distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And with that we have the assumptions required to apply the normal distribution to create the confidence interval since the distribution for \bar X is normal.

Part b

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

275-2.58\frac{60}{\sqrt{1077}}=270.283    

275+2.58\frac{60}{\sqrt{1077}}=279.717

So on this case the 99% confidence interval would be given by (270.283;3279.717)    

270.283\leq \mu \leq 279.717

Part c

We are confident (99%) that the true mean for the quantitative scores for young women is between (270.283;3279.717)

8 0
3 years ago
Please help me with this
Dennis_Churaev [7]

Prob ( guessing right) = 0.25 . Get 1 point.

Prob( guessing wrong) = 0.75. Lose 0.5 points.

Expected value = 1(0.25) + (-0.5)(0.75)

= -0.125 answer

4 0
3 years ago
Read 2 more answers
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